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Using concentrations of solutions in mol/dm3: AQA GCSE Chemistry questions

Every AQA GCSE Chemistry exam question on 4.3.4 Using concentrations of solutions in mol/dm3, 2018–2025, with its mark scheme and examiner’s report.

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1,744 questions

  1. Q06.2

    June 2024 · Paper 1 Higher

    6 marks4.3.4 Using concentrations of solutions in mol/dm34.5.2 Chemical cells and fuel cells
    The whole paper ↗
    June 2024 Paper 1 Higher, question 06.2: The voltage produced by a chemical cell depends on the concentration of the electrolyte solution. Plan an experiment to investigate how the voltage produced by

  2. Q09.4

    June 2024 · Paper 1 Higher

    2 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    June 2024 Paper 1 Higher, question 09.4: The student titrated a solution containing 0.0045 moles of sodium hydroxide with 0.15 mol/dm3 hydrochloric acid. The equation for the reaction is: NaOH + HCl →

  3. Q09.4

    June 2024 · Paper 2 Higher

    2 marks4.3.2 Use of amount of substance in relation to masses of pure substances4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    June 2024 Paper 2 Higher, question 09.4: Figure 13 shows the results for 0.40 mol/dm3 sulfuric acid. Figure 13 The student repeated the experiment using 0.20 mol/dm3 sulfuric acid instead of 0.40 mol/d

  4. Q05.5

    June 2023 · Paper 1 Higher

    5 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    June 2023 Paper 1 Higher, question 05.5: A student does a titration using sodium carbonate solution and nitric acid. The equation for the reaction is: Na2CO3 + 2 HNO3 → 2 NaNO3 + CO2 + H2O 25.0 cm3 of

  5. Q07.4

    June 2023 · Paper 2 Higher

    2 marks4.3.4 Using concentrations of solutions in mol/dm34.6.1 Rate of reaction
    The whole paper ↗
    June 2023 Paper 2 Higher, question 07.4: The results for 50 cm3 of 2.0 mol/dm3 hydrogen peroxide solution and 1.0 g of manganese dioxide are shown again on Figure 5. Figure 5 The student repeated the i

  6. Q08.3

    June 2022 · Paper 1 Higher

    4 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    June 2022 Paper 1 Higher, question 08.3: 25.00 cm3 of the hydrochloric acid reacted with 23.50 cm3 of the 0.100 mol/dm3 barium hydroxide solution. The equation for the reaction is: 2 HCl(aq) + Ba(OH)2(

  7. Q09.4

    November 2021 · Paper 1 Higher

    2 marks4.3.2 Use of amount of substance in relation to masses of pure substances4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    November 2021 Paper 1 Higher, question 09.4: Ethanedioic acid is a solid at room temperature. Calculate the mass of ethanedioic acid (H2C2O4) needed to make 250 cm3 of a solution with concentration 0.0480

  8. Q09.5

    November 2021 · Paper 1 Higher

    3 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    November 2021 Paper 1 Higher, question 09.5: The student found that 25.0 cm3 of the sodium hydroxide solution was neutralised by 15.00 cm3 of the 0.0480 mol/dm3 ethanedioic acid solution. The equation for

  9. Q09.4

    November 2020 · Paper 1 Higher

    3 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    November 2020 Paper 1 Higher, question 09.4: The student made 250 cm3 of a solution of citric acid of concentration 0.0500 mol/dm3 Calculate the mass of citric acid (C6H8O7) required. Relative atomic masse

  10. Q09.7

    November 2020 · Paper 1 Higher

    3 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    November 2020 Paper 1 Higher, question 09.7: 13.3 cm3 of 0.0500 mol/dm3 citric acid solution was needed to neutralise 25.0 cm3 of sodium hydroxide solution. The equation for the reaction is: 3 NaOH + C6H8O

  11. Q09.5

    June 2019 · Paper 1 Higher

    6 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    June 2019 Paper 1 Higher, question 09.5: The student repeated the investigation. The student used solutions that had different concentrations from the first investigation. The student found that 15.5 c

  12. Q09.1

    June 2018 · Paper 1 Higher

    2 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    June 2018 Paper 1 Higher, question 09.1: Dilute hydrochloric acid is a strong acid. Explain why an acid can be described as both strong and dilute. [2 marks]

  13. Q09.3

    June 2018 · Paper 1 Higher

    5 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    June 2018 Paper 1 Higher, question 09.3: Table 4 shows the student’s results. Table 4 Titration 1 Titration 2 Titration 3 Titration 4 Titration 5 Volume of sodium hydroxide solution in cm3 23.50 21.10

  14. Q09.5

    June 2018 · Paper 1 Higher

    2 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    June 2018 Paper 1 Higher, question 09.5: Calculate the mass of sodium hydroxide in 30.0 cm3 of a 0.105 mol/dm3 solution. Relative formula mass (Mr): NaOH = 40 [2 marks] Mass of sodium hydroxide = g

  15. Q08.3

    Specimen · Paper 1 Higher

    4 marks4.3.4 Using concentrations of solutions in mol/dm34.4.2 Reactions of acids
    The whole paper ↗
    Specimen Paper 1 Higher, question 08.3: Describe how the student would complete the titration. You should name a suitable indicator and give the colour change that would be seen. [4 marks 8

  16. Q08.5

    Specimen · Paper 1 Higher

    4 marks4.3.4 Using concentrations of solutions in mol/dm3
    The whole paper ↗
    Specimen Paper 1 Higher, question 08.5: The equation for the reaction is: 2NaOH + H2SO4 → Na2SO4 + 2H2O Calculate the concentration of the sodium hydroxide. Give your answer to three significant figur

  17. Q08.6

    Specimen · Paper 1 Higher

    2 marks4.3.4 Using concentrations of solutions in mol/dm3
    Mark scheme (PDF)
    The whole paper ↗
    Specimen Paper 1 Higher, question 08.6: The student did another experiment using 20 cm3 of sodium hydroxide solution with a concentration of 0.18 mol/dm3. Relative formula mass (Mr) of NaOH = 40 Calcu
All 17 questions on Using concentrations of solutions in mol/dm3, as a list
  1. June 2024, Paper 1 Higher, Q06.2 (6 marks): The voltage produced by a chemical cell depends on the concentration of the electrolyte solution. Plan an experiment to investigate how the voltage produced by
  2. June 2024, Paper 1 Higher, Q09.4 (2 marks): The student titrated a solution containing 0.0045 moles of sodium hydroxide with 0.15 mol/dm3 hydrochloric acid. The equation for the reaction is: NaOH + HCl →
  3. June 2024, Paper 2 Higher, Q09.4 (2 marks): Figure 13 shows the results for 0.40 mol/dm3 sulfuric acid. Figure 13 The student repeated the experiment using 0.20 mol/dm3 sulfuric acid instead of 0.40 mol/d
  4. June 2023, Paper 1 Higher, Q05.5 (5 marks): A student does a titration using sodium carbonate solution and nitric acid. The equation for the reaction is: Na2CO3 + 2 HNO3 → 2 NaNO3 + CO2 + H2O 25.0 cm3 of
  5. June 2023, Paper 2 Higher, Q07.4 (2 marks): The results for 50 cm3 of 2.0 mol/dm3 hydrogen peroxide solution and 1.0 g of manganese dioxide are shown again on Figure 5. Figure 5 The student repeated the i
  6. June 2022, Paper 1 Higher, Q08.3 (4 marks): 25.00 cm3 of the hydrochloric acid reacted with 23.50 cm3 of the 0.100 mol/dm3 barium hydroxide solution. The equation for the reaction is: 2 HCl(aq) + Ba(OH)2(
  7. November 2021, Paper 1 Higher, Q09.4 (2 marks): Ethanedioic acid is a solid at room temperature. Calculate the mass of ethanedioic acid (H2C2O4) needed to make 250 cm3 of a solution with concentration 0.0480
  8. November 2021, Paper 1 Higher, Q09.5 (3 marks): The student found that 25.0 cm3 of the sodium hydroxide solution was neutralised by 15.00 cm3 of the 0.0480 mol/dm3 ethanedioic acid solution. The equation for
  9. November 2020, Paper 1 Higher, Q09.4 (3 marks): The student made 250 cm3 of a solution of citric acid of concentration 0.0500 mol/dm3 Calculate the mass of citric acid (C6H8O7) required. Relative atomic masse
  10. November 2020, Paper 1 Higher, Q09.7 (3 marks): 13.3 cm3 of 0.0500 mol/dm3 citric acid solution was needed to neutralise 25.0 cm3 of sodium hydroxide solution. The equation for the reaction is: 3 NaOH + C6H8O
  11. June 2019, Paper 1 Higher, Q09.5 (6 marks): The student repeated the investigation. The student used solutions that had different concentrations from the first investigation. The student found that 15.5 c
  12. June 2018, Paper 1 Higher, Q09.1 (2 marks): Dilute hydrochloric acid is a strong acid. Explain why an acid can be described as both strong and dilute. [2 marks]
  13. June 2018, Paper 1 Higher, Q09.3 (5 marks): Table 4 shows the student’s results. Table 4 Titration 1 Titration 2 Titration 3 Titration 4 Titration 5 Volume of sodium hydroxide solution in cm3 23.50 21.10
  14. June 2018, Paper 1 Higher, Q09.5 (2 marks): Calculate the mass of sodium hydroxide in 30.0 cm3 of a 0.105 mol/dm3 solution. Relative formula mass (Mr): NaOH = 40 [2 marks] Mass of sodium hydroxide = g
  15. Specimen, Paper 1 Higher, Q08.3 (4 marks): Describe how the student would complete the titration. You should name a suitable indicator and give the colour change that would be seen. [4 marks 8
  16. Specimen, Paper 1 Higher, Q08.5 (4 marks): The equation for the reaction is: 2NaOH + H2SO4 → Na2SO4 + 2H2O Calculate the concentration of the sodium hydroxide. Give your answer to three significant figur
  17. Specimen, Paper 1 Higher, Q08.6 (2 marks): The student did another experiment using 20 cm3 of sodium hydroxide solution with a concentration of 0.18 mol/dm3. Relative formula mass (Mr) of NaOH = 40 Calcu

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