Yield and atom economy of chemical reactions: AQA GCSE Chemistry questions
Every AQA GCSE Chemistry exam question on 4.3.3 Yield and atom economy of chemical reactions, 2018–2025, with its mark scheme and examiner’s report.
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Q03.3
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Q03.6
The whole paper ↗![June 2025 Paper 1 Higher, question 03.6: The reaction producing tungsten has a high atom economy. Why is it important to use reactions with a high atom economy in industry? [1 mark]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84621h-jun25-03-6-qp.webp)
Q07.3
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Q10.3
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Q10.6
The whole paper ↗![June 2025 Paper 1 Foundation, question 10.6: The reaction producing tungsten has a high atom economy. Why is it important to use reactions with a high atom economy in industry? [1 mark]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84621f-jun25-10-6-qp.webp)
Q01.5
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Q08.5
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Q09.6
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Q08.4
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Q08.7
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Q07.2
The whole paper ↗![June 2022 Paper 2 Higher, question 07.2: How does the equation for the reaction show that the atom economy of the forward reaction is 100%? [1 mark]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84622h-jun22-07-2-qp.webp)
Q05.3
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Q03.3
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Q10.3
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Q07.3
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Q07.4
The whole paper ↗![November 2021 Paper 2 Foundation, question 07.4: What are two possible reasons why the percentage yield of ethanol is less than 100%? [2 marks] Tick () two boxes. Ethanol is the only product of the reaction.](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84622f-nov21-07-4-qp.webp)
Q03.5
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Q03.6
The whole paper ↗![November 2020 Paper 1 Higher, question 03.6: Give one reason why reactions with a high atom economy are used in industry. [1 mark]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84621h-nov20-03-6-qp.webp)
Q10.5
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Q10.6
The whole paper ↗![November 2020 Paper 1 Foundation, question 10.6: Give one reason why reactions with a high atom economy are used in industry. [1 mark]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/84621f-nov20-10-6-qp.webp)
All 32 questions on Yield and atom economy of chemical reactions, as a list
- June 2025, Paper 1 Higher, Q03.3 (3 marks): Cadmium (Cd) can be extracted by the reaction of cadmium oxide with carbon. The equation for the reaction is: CdO + C ⟶ Cd + CO Calculate the percentage atom ec
- June 2025, Paper 1 Higher, Q03.6 (1 mark): The reaction producing tungsten has a high atom economy. Why is it important to use reactions with a high atom economy in industry? [1 mark]
- June 2025, Paper 1 Foundation, Q07.3 (2 marks): A mixture of salt and sand contained 16.0 g of salt. The student obtained 13.6 g of salt after separation from the mixture. Calculate the percentage yield of th
- June 2025, Paper 1 Foundation, Q10.3 (3 marks): Cadmium (Cd) can be extracted by the reaction of cadmium oxide with carbon. The equation for the reaction is: CdO + C ⟶ Cd + CO Calculate the percentage atom ec
- June 2025, Paper 1 Foundation, Q10.6 (1 mark): The reaction producing tungsten has a high atom economy. Why is it important to use reactions with a high atom economy in industry? [1 mark]
- June 2024, Paper 1 Higher, Q01.5 (3 marks): The maximum theoretical mass of the salt that could be produced using 50 cm3 of the sulfuric acid is 12.5 g. The percentage yield of the salt is 92.8%. Calculat
- June 2024, Paper 1 Foundation, Q08.5 (3 marks): The maximum theoretical mass of the salt that could be produced using 50 cm3 of the sulfuric acid is 12.5 g. The percentage yield of the salt is 92.8%. Calculat
- June 2023, Paper 1 Higher, Q09.6 (4 marks): Metal X is extracted from an oxide of metal X by reaction with hydrogen. The equation for the reaction is: XO3 + 3 H2 → X + 3 H2O The percentage atom economy fo
- June 2023, Paper 1 Foundation, Q08.4 (2 marks): Copper oxide reacts with hydrogen to produce copper. The equation for the reaction is: CuO + H2 → Cu + H2O Calculate the percentage atom economy for obtaining c
- June 2022, Paper 1 Foundation, Q08.7 (2 marks): Titanium can be produced from titanium oxide by electrolysis. The equation for the reaction is: TiO2 → Ti + O2 Calculate the percentage atom economy for the pro
- June 2022, Paper 2 Higher, Q07.2 (1 mark): How does the equation for the reaction show that the atom economy of the forward reaction is 100%? [1 mark]
- June 2022, Paper 2 Foundation, Q05.3 (1 mark): The word equation for the production of ammonia is: nitrogen + hydrogen ⇌ ammonia The atom economy of the reaction is 100%. How does the word equation show that
- November 2021, Paper 1 Higher, Q03.3 (3 marks): Carbon is used to extract tin (Sn) from tin oxide (SnO2). The equation for the reaction is: SnO2 + C → Sn + CO2 Calculate the percentage atom economy for extrac
- November 2021, Paper 1 Foundation, Q10.3 (3 marks): Carbon is used to extract tin (Sn) from tin oxide (SnO2). The equation for the reaction is: SnO2 + C → Sn + CO2 Calculate the percentage atom economy for extrac
- November 2021, Paper 2 Foundation, Q07.3 (2 marks): The reaction produces a maximum theoretical mass of 400 kg of ethanol from 243 kg of ethene and 157 kg of steam. A company produces 380 kg of ethanol from 243 k
- November 2021, Paper 2 Foundation, Q07.4 (2 marks): What are two possible reasons why the percentage yield of ethanol is less than 100%? [2 marks] Tick () two boxes. Ethanol is the only product of the reaction.
- November 2020, Paper 1 Higher, Q03.5 (4 marks): Calculate the percentage atom economy for the production of silver iodide in this reaction. The equation for the reaction is: AgNO3(aq) + NaI(aq) → AgI(s) + NaN
- November 2020, Paper 1 Higher, Q03.6 (1 mark): Give one reason why reactions with a high atom economy are used in industry. [1 mark]
- November 2020, Paper 1 Foundation, Q10.5 (4 marks): Calculate the percentage atom economy for the production of silver iodide in this reaction. The equation for the reaction is: AgNO3(aq) + NaI(aq) → AgI(s) + NaN
- November 2020, Paper 1 Foundation, Q10.6 (1 mark): Give one reason why reactions with a high atom economy are used in industry. [1 mark]
- June 2019, Paper 1 Foundation, Q06.1 (2 marks): Tungsten is a metal. The symbol of tungsten is W Tungsten is produced from tungsten oxide by reaction with hydrogen. The equation for the reaction is: WO3 + 3 H
- June 2019, Paper 1 Foundation, Q06.4 (3 marks): 60.0 kg of aluminium oxide produces a maximum of 31.8 kg of aluminium. In an extraction process only 28.4 kg of aluminium is produced from 60.0 kg of aluminium
- June 2018, Paper 1 Higher, Q02.5 (3 marks): An equation for the reaction is: NiO + C Ni + CO Calculate the percentage atom economy for the reaction to produce nickel. Relative atomic masses (Ar): C = 12
- June 2018, Paper 1 Higher, Q08.8 (2 marks): For a Stage 2 reaction the percentage yield was 92.3% The theoretical maximum mass of titanium produced in this batch was 13.5 kg. Calculate the actual mass of
- June 2018, Paper 1 Foundation, Q02.6 (2 marks): The company calculates that 500 g of titanium dioxide should produce 1.2 kg of titanium chloride. However, the company finds that 500 g of titanium dioxide only
- June 2018, Paper 1 Foundation, Q09.5 (3 marks): An equation for the reaction is: NiO + C Ni + CO Calculate the percentage atom economy for the reaction to produce nickel. Relative atomic masses (Ar): C = 12
- Specimen, Paper 1 Higher, Q05.3 (2 marks): The percentage yield of copper chloride was 79.1 %. Calculate the mass of copper chloride the student actually produced. [2 marks] Actual mass of copper chlorid
- Specimen, Paper 1 Higher, Q05.4 (3 marks): Look at the equations for the two reactions: Reaction 1 CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g) Reaction 2 CuO(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) Reac
- Specimen, Paper 1 Higher, Q05.5 (1 mark): The atom economy for Reaction 1 is 68.45 %. Compare the atom economies of the two reactions for making copper chloride. Give a reason for the difference. [1 mar
- Specimen, Paper 1 Foundation, Q06.4 (3 marks): The percentage atom economy for a reaction is calculated using:
- Specimen, Paper 1 Foundation, Q06.5 (1 mark): Give one reason why is it important for the percentage atom economy of a reaction to be as high as possible. 8
- Specimen, Paper 2 Foundation, Q07.4 (2 marks): Use Figure 8 to determine the difference in percentage yield of ammonia at 150 atmospheres pressure and 250 atmospheres pressure. [2 marks] Difference in percen
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