plumiShapes of complexes, including cis-platin: Edexcel International A Level Chemistry questions
Edexcel International A Level Chemistry past-paper questions on 17.1.5 Shapes of complexes, including cis-platin, 2019–2025, with mark schemes and examiner’s reports where available.
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All 26 questions on Shapes of complexes, including cis-platin, as a list
- June 2025, Unit 5, Q6 (1 mark): Which is incorrect for H2O, OH − and NH3? A all can act as bidentate ligands B all can act as electron pair donors C all can form dative covalent bonds D all ca
- June 2025, Unit 5, Q15(a) (1 mark): State the shape of the cis-platin complex. (1)
- June 2025, Unit 5, Q15(b) (1 mark): Draw the isomer trans-platin. (1)
- June 2025 (A), Unit 5, Q7(a) (1 mark): Which complex has a tetrahedral structure? (1) A [CrCl4]– B [Cu(NH3)4(H2O)2]2+ C [Pt(NH3)2Cl2] D [TiCl6]2–
- June 2025 (A), Unit 5, Q16(a)(i) (1 mark): Draw the shape of this complex ion. (1)
- January 2025, Unit 5, Q7 (1 mark): What are the shapes of the complexes [CuCl4]2– and Pt(NH3)2Cl2? [CuCl4]2– Pt(NH3)2Cl2 A square planar square planar B square planar tetrahedral C tetrahedral sq
- January 2024, Unit 5, Q17(b)(i) (1 mark): Write the balanced equation for Step 1. State symbo
- January 2024, Unit 5, Q17(b)(iii) (2 marks): trans‑Platin binds to DNA. Suggest why this does not damage the DNA. (2)
- January 2024, Unit 5, Q17(c)(ii) (2 marks): Draw a diagram of the anion of Reinecke’s salt showing its three‑dimensional shape. (2)
- January 2024, Unit 5, Q17(d)(i) (2 marks): Explain why the tetrahedral complex [Co(NH3)ClBrI] exists as two optical isomers. (2)
- January 2024, Unit 5, Q17(d)(ii) (1 mark): Complete the diagram showing the two optical isomers of the tetrahedral complex. (1) Co Co
- October 2023, Unit 5, Q19(c)(i) (2 marks): Explain how water acts as a monodentate ligand. (2)
- October 2023, Unit 5, Q19(c)(ii) (2 marks): Explain the shape of the [Fe(H2O)6]2+ complex ion. (2)
- June 2023, Unit 5, Q8 (1 mark): Which complex contains only monodentate ligands? A [Fe(CN)6]4– B [Cr(C2O4)3]3– C [Ni(EDTA)]2– D [Co(NH2CH2CH2NH2)2Cl2]
- June 2023, Unit 5, Q9 (1 mark): Which complex has a ligand-metal-ligand bond angle of 109.5°? A [CuCl4]2– B [Fe(EDTA)]– C [Ag(NH3)2]+ D [Pt(NH3)2Cl2]
- October 2022, Unit 5, Q7 (1 mark): Platinum forms a complex with the formula Pt(NH3)2Cl2 which is used in cancer treatment. Three possible structures of this complex are shown. Cl Cl NH NH3 Cl NH
- October 2022, Unit 5, Q22(b)(iii) (2 marks): Explain why the shape of the complex ion changes when concentrated hydrochloric acid is added. (2)
- June 2022, Unit 5, Q4 (1 mark): Which transition metal complex is commonly used as a treatment for cancer? 2– Cl A Cu Cu Cl Cl Cl + NCCH NCCH3 B Cu Cu NCCH NCCH3 H3CCN CCN NCCH NCCH3 Cl NH NH3
- January 2022, Unit 5, Q1(b) (1 mark): Which complex is tetrahedral? (1) A [Pt(NH3)2Cl2] B [Cu(H2O)4(OH)2] C [Cu(NH3)4(H2O)2]2+ D [CoCl4]2−
- January 2022, Unit 5, Q10(a)(i) (3 marks): Explain the shape of [Ag(NH3)2]+ . (3)
- October 2021, Unit 5, Q18(c) (1 mark): Complex ion C has six cyanide ligands. Draw the structure of C, clearly showing its three‑dimensional shape. (1)
- October 2021, Unit 5, Q20(b)(ii) (1 mark): Complex Z is a stereoisomer of complex Y. Complete the diagram to show the arrangement of the ligands in complex Z. (1) Cl Ti3+ complex Z
- October 2021, Unit 5, Q21(c) (2 marks): Curcumin anions can act as bidentate ligands in metal‑curcumin (M‑curc) complexes. The oxygen atoms of the curc ligand occupy adjacent coordination sites in the
- June 2021, Unit 5, Q21(f) (1 mark): Give a possible reason why the chloro complexes of iron ions have a coordination number of four rather than six. (1)
- January 2021, Unit 5, Q7(a) (1 mark): What are the shapes of these complexes? (1) A both complexes are square planar B both complexes are tetrahedral − is square planar C Pt(NH3)2Cl2 is tetrahedral
- October 2020, Unit 5, Q25(c)(ii) (1 mark): The Lanthanides The lanthanides form a series in the Periodic Table comprising the elements from lanthanum, La (Z = 57) to lutetium, Lu (Z = 71). They have impo
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