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Temperature and the Arrhenius equation: OCR A‑Level Chemistry A questions

OCR A-Level Chemistry A past-paper questions on 5.1.1.5 Temperature and the Arrhenius equation, 2016–2025, with mark schemes and examiner’s reports where available.

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  1. Q18(c)(i)

    June 2025 · Paper 1

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  2. Q18(c)(ii)

    June 2025 · Paper 1

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  3. Q9

    June 2024 · Paper 1

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  4. Q21(b)(i)

    November 2021 · Paper 1

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  5. Q21(b)(ii)

    November 2021 · Paper 1

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  6. Q21(b)(iii)

    November 2021 · Paper 1

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  7. Q8

    November 2020 · Paper 1

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  8. Q11

    June 2019 · Paper 1

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  9. Q17(b)(i)

    June 2018 · Paper 1

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  10. Q17(b)(ii)

    June 2018 · Paper 1

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  11. Q3(a)(ii)

    June 2017 · Paper 3

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All 11 questions on Temperature and the Arrhenius equation, as a list
  1. June 2025, Paper 1, Q18(c)(i) (1 mark): Complete the table by adding the missing value of ln k. [1]
  2. June 2025, Paper 1, Q18(c)(ii) (4 marks): Plot a graph of ln k against 1 T on the grid opposite. Use your graph to calculate the value of the activation energy, Ea, in kJ mol–1. Give your answer to 2 si
  3. June 2024, Paper 1, Q9 (1 mark): A graph of ln(k) is plotted against 1 / T for a reaction. (k = rate constant, T = temperature in K.) The gradient has the numerical value of –16 000. What is th
  4. November 2021, Paper 1, Q21(b)(i) (3 marks): Calculate the activation energy, Ea, for Reaction 21.1, in kJ mol–1. Give your answer to 3 significant figures. Ea = kJ mol–1 [3]
  5. November 2021, Paper 1, Q21(b)(ii) (1 mark): From the graph the student estimates the value of ln A as –2.00. (A is the pre-exponential factor.) Explain what mistake the student has made. [1]
  6. November 2021, Paper 1, Q21(b)(iii) (2 marks): The student calculates the value of k in Investigation 1 as 0.075 s–1. Using Graph 21.2, determine the temperature, in °C, at which Investigation 1 was carried
  7. November 2020, Paper 1, Q8 (1 mark): A graph is plotted of ln(k) against 1 /T. (k = rate constant, T = temperature in K) The gradient has the numerical value of −55 000. What is the activation ener
  8. June 2019, Paper 1, Q11 (1 mark): A graph of ln k against 1 T (T in K) for a reaction has a gradient with the numerical value of −4420. What is the activation energy, in kJ mol−1, for this react
  9. June 2018, Paper 1, Q17(b)(i) (3 marks): Draw a best-fit straight line and calculate the activation energy, in J mol–1. Give your answer to three significant figures. Show your working. activation ener
  10. June 2018, Paper 1, Q17(b)(ii) (2 marks): Use the graph to calculate the value of the pre-exponential factor, A. Show your working. pre-exponential factor, A = [2]
  11. June 2017, Paper 3, Q3(a)(ii) (3 marks): The rate constant, k, for this reaction is determined at different temperatures, T. Explain how the student could determine the activation energy, Ea, for the r

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