Transformers and the National Grid: Edexcel GCSE Physics questions
Every Edexcel GCSE Physics exam question on Transformers and the National Grid (specification points 13.5–13.11), 2018–2025, with its mark scheme and examiner’s report.
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Calculations
Q6(a)(i)
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Q6(a)(ii)
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Q9(d)
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Q10(b)
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Q10(b)
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Q5(b)
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Q5(c)(i)
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Q5(c)(ii)
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Q5(c)(iii)
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Q10(b)
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Q10(c)
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Q9(a)(i)
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Q9(a)(ii)
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Q9(b)
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Q5(c)
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Q7(c)(i)
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Q7(c)(ii)
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Q2(c)
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Q6(b)(i)
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Q6(b)(ii)
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All 28 questions on Transformers and the National Grid, as a list
- June 2025, Paper 2 Higher, Q6(a)(i) (3 marks): Explain how the current is produced in the secondary coil of the transformer in Figure 9. (3)
- June 2025, Paper 2 Higher, Q6(a)(ii) (2 marks): The potential difference across the primary coil is 230 V. The potential difference across the secondary coil is 1.5 V. The primary coil has 1840 turns of wire.
- June 2025, Paper 2 Foundation, Q9(d) (6 marks): Figure 18 is a diagram showing a part of the National Grid, used to supply electrical power to homes. overhead power lines 132 000 V 230 V 25 000 V home power s
- June 2024, Paper 2 Higher, Q10(b) (6 marks): A transformer converts a voltage of 11 000 V to 230 V. Explain how the design of this transformer enables the voltage to be converted from 11 000 V to 230 V. Yo
- June 2023, Paper 2 Higher, Q10(b) (3 marks): Figure 25 shows a transformer. soft iron core Vp Np Ns Figure 25 The number of turns on the primary coil, Np = 800 The potential difference across the primary c
- June 2023, Paper 2 Foundation, Q5(b) (2 marks): Explain why the National Grid uses high voltages with small currents to transfer electricity from power stations. (2)
- June 2023, Paper 2 Foundation, Q5(c)(i) (2 marks): Calculate the power in the primary coil. Use the equation P = V×I (2) power in the primary coil = W
- June 2023, Paper 2 Foundation, Q5(c)(ii) (2 marks): Calculate the following for the transformer in Figure 12. number of turns in secondary coil number of turns in primary coil (2)
- June 2023, Paper 2 Foundation, Q5(c)(iii) (2 marks): For the transformer in Figure 12, evaluate, in its simplest form, the ratio secondary voltage : primary voltage (2) :
- June 2022, Paper 2 Higher, Q10(b) (3 marks): This question is about a transformer. iron core primary coil secondary coil 700 turns of wire 400 turns of wire primary voltage = 230 V secondary current = 1.75
- June 2022, Paper 2 Higher, Q10(c) (6 marks): Figure 22 shows how electricity is delivered efficiently from a power station (P) to homes (T). not to scale R T P Q S Figure 22 Using Figure 22, explain the st
- November 2021, Paper 2 Higher, Q9(a)(i) (1 mark): The size of the potential difference (voltage) across the secondary coil is (1) A twice the size of the current in the primary coil B half the size of the curre
- November 2021, Paper 2 Higher, Q9(a)(ii) (3 marks): Explain how an alternating current in the primary coil causes an alternating current in the secondary coil of the transformer. (3)
- November 2021, Paper 2 Higher, Q9(b) (2 marks): The primary coil of a different transformer is connected to the 230 V mains supply. The voltage across the secondary coil is 15 V. The primary coil has 600 turn
- November 2021, Paper 2 Foundation, Q5(c) (3 marks): A transformer is used to connect a laptop computer to the mains electricity supply. The input voltage to the transformer is 230 V. The output current from the t
- November 2020, Paper 2 Higher, Q7(c)(i) (1 mark): State the purpose of the transformer shown in Figure 18. (1)
- November 2020, Paper 2 Higher, Q7(c)(ii) (3 marks): Calculate the output voltage of the secondary coil. Use an equation selected from the list of equations at the end of this paper. (3) output voltage = V
- November 2020, Paper 2 Foundation, Q2(c) (2 marks): The transformer in another battery charger has a primary coil and a secondary coil. The voltage across the primary coil = 230 V. The voltage across the secondar
- June 2019, Paper 2 Higher, Q6(b)(i) (2 marks): Describe the cause of the changing magnetic field in the core of the transformer. (2)
- June 2019, Paper 2 Higher, Q6(b)(ii) (3 marks): A potential difference of 230 V is applied across the primary coil of a transformer. There is a potential difference of 15 V across the secondary coil. The prim
- June 2018, Paper 2 Higher, Q9(b)(i) (2 marks): Figure 17 shows the output from a battery. current 0 time Figure 17 Explain why a transformer will not work with the input current as shown in Figure 17. (2)
- June 2018, Paper 2 Higher, Q9(b)(ii) (3 marks): A transformer has 30 turns on the primary coil and 150 turns on the secondary coil. A potential difference of 25 V is applied across the primary coil. Calculate
- June 2018, Paper 2 Higher, Q9(c) (6 marks): High voltage transmission cables and transformers are used in the national grid. Explain how using high voltage transmission cables and transformers allows the
- June 2018, Paper 2 Foundation, Q1(a)(i) (1 mark): Electrical power is generated at (1)
- June 2018, Paper 2 Foundation, Q1(a)(ii) (1 mark): Electricity is transmitted over long distances by transmission lines that are part of (1)
- June 2018, Paper 2 Foundation, Q1(a)(iii) (1 mark): Electricity is transmitted at high voltages so that (1)
- June 2018, Paper 2 Foundation, Q1(b) (1 mark): Which statement is true for transformers? (1) A Transformers can only step-up voltages. B Transformers can only step-down voltages. C Transformers can work with
- June 2018, Paper 2 Foundation, Q1(c) (2 marks): In a small transformer ● the primary voltage is 230 V ● the primary current is 0.020 A ● the secondary voltage is 5.0 V Calculate the secondary current. Use the
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