plumiCharacteristics of alternating currents: CAIE A‑Level Physics questions
Every CAIE A-Level Physics exam question on 21.1 Characteristics of alternating currents, June 2024 and the specimen papers, with its mark scheme and examiner’s report.
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Calculations
Q7(b)(i)
The whole paper ↗![June 2024 Paper 4, question 7(b)(i): The load resistor R has a resistance of 370 Ω. Show that the maximum power dissipated in R is 0.22 W. [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/970241-jun24-07-bi-qp.webp)
Q7(b)(ii)
The whole paper ↗![June 2024 Paper 4, question 7(b)(ii): On Fig. 7.3, sketch the variation with t of the power P dissipated in R. 0.4 P / W 0.2 0 0 0.02 0.04 0.06 0.08 t / s Fig. 7.3 [3]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/970241-jun24-07-bii-qp.webp)
Q7(b)(iii)
The whole paper ↗![June 2024 Paper 4, question 7(b)(iii): Calculate the mean power dissipated in R. mean power = W [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/970241-jun24-07-biii-qp.webp)
Q7(c)
The whole paper ↗
Q5(a)(i)
The whole paper ↗![Specimen Paper 4, question 5(a)(i): Determine the root-mean-square (r.m.s.) value of the supply potential difference before rectification. r.m.s. potential difference = V [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/970204-spec-05-ai-qp.webp)
All 5 questions on Characteristics of alternating currents, as a list
- June 2024, Paper 4, Q7(b)(i) (2 marks): The load resistor R has a resistance of 370 Ω. Show that the maximum power dissipated in R is 0.22 W. [2]
- June 2024, Paper 4, Q7(b)(ii) (3 marks): On Fig. 7.3, sketch the variation with t of the power P dissipated in R. 0.4 P / W 0.2 0 0 0.02 0.04 0.06 0.08 t / s Fig. 7.3 [3]
- June 2024, Paper 4, Q7(b)(iii) (1 mark): Calculate the mean power dissipated in R. mean power = W [1]
- June 2024, Paper 4, Q7(c) (2 marks): The circuit of Fig. 7.1 is disconnected, and R is connected directly across the power supply. Explain, without calculation, how the mean power now dissipated in
- Specimen, Paper 4, Q5(a)(i) (2 marks): Determine the root-mean-square (r.m.s.) value of the supply potential difference before rectification. r.m.s. potential difference = V [2]
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