Patterns of inheritance: OCR A‑Level Biology A questions
Every OCR A-Level Biology A exam question on 6.1.2 Patterns of inheritance, 2016–2025, with its mark scheme and examiner’s report.
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Q17(b)(ii)
The whole paper ↗![June 2025 Paper 2, question 17(b)(ii): Suggest why female mammals cannot produce male offspring by parthenogenesis. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h42002-jun25-17-bii-qp.webp?v=3)
Q20(a)(i)
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Q20(a)(ii)
The whole paper ↗![June 2025 Paper 2, question 20(a)(ii): Explain why epistasis affects the offspring ratio in a genetic cross. [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h42002-jun25-20-aii-qp.webp?v=3)
Q20(b)(i)
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Q20(b)(ii)
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Q5(a)
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Q3(c)
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Q4(b)(i)
The whole paper ↗![June 2023 Paper 3, question 4(b)(i): State the term for a large decrease in population size that reduces the gene pool. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h42003-jun23-04-bi-qp.webp?v=3)
Q4(b)(iii)
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Q5(c)
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Q19(a)(i)
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Q19(a)(ii)
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Q19(b)(i)
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Q19(b)(ii)
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All 57 questions on Patterns of inheritance, as a list
- June 2025, Paper 2, Q12 (1 mark): Artificial selection and natural selection are similar processes. Which option describes only natural selection? A Alleles are passed on to the next generation.
- June 2025, Paper 2, Q13 (1 mark): Reproduction can be sexual or asexual. What is an advantage of sexual reproduction? A Advantageous features are preserved between generations. B Genetic variati
- June 2025, Paper 2, Q17(b)(ii) (1 mark): Suggest why female mammals cannot produce male offspring by parthenogenesis. [1]
- June 2025, Paper 2, Q20(a)(i) (3 marks): Sweet pea is another species of plant. • Sweet pea flower colour is coded for by a gene with two alleles: blue (B) and red (b). • Sweet pea pollen shape is code
- June 2025, Paper 2, Q20(a)(ii) (2 marks): Explain why epistasis affects the offspring ratio in a genetic cross. [2]
- June 2025, Paper 2, Q20(b)(i) (3 marks): Use the Hardy–Weinberg principle to calculate the number of heterozygous individuals in the greenhouse. Use the equations: p + q = 1 p2 + 2pq + q2 = 1 Number of
- June 2025, Paper 2, Q20(b)(ii) (1 mark): Estimates made by using the Hardy–Weinberg principle can be inaccurate. Use the information above to suggest one reason why the answer calculated in part (b)(i)
- June 2024, Paper 2, Q5 (1 mark): Variation can be under genetic control. Which statement about the genetic control of variation cannot be true for discontinuous variation? A Variation is contro
- June 2024, Paper 3, Q5(a) (6 marks): Type 1 diabetes mellitus is characterised by a lack of insulin production. Type 2 diabetes mellitus can involve reduced production of insulin and a decreased re
- June 2023, Paper 2, Q4 (1 mark): Scientists crossed two plants that were heterozygous for two different genes. Both plants had the same genotype, AaBb. The genotypes and ratios of the offspring
- June 2023, Paper 2, Q12 (1 mark): The modern pedigree dog breeds have been produced by many years of selective breeding. Which option does not explain why genetic disorders are common in pedigre
- June 2023, Paper 2, Q13 (1 mark): What step could be taken to reduce the occurrence of genetic disorders in pedigree dogs? A Breeding only with individuals that meet the official breed descripti
- June 2023, Paper 3, Q3(c) (4 marks): Two characteristics that farmers have selectively bred in maize are colour and kernel (fruit) shape. Colour is determined by a gene with two alleles: • Allele A
- June 2023, Paper 3, Q4(b)(i) (1 mark): State the term for a large decrease in population size that reduces the gene pool. [1]
- June 2023, Paper 3, Q4(b)(iii) (4 marks): The kakapo and two other species of bird, the kaka and the kea, evolved from a common ancestor approximately 70 million years ago. The evolutionary timeline of
- June 2022, Paper 3, Q5(c) (2 marks): The Hardy-Weinberg principle can be used to calculate allele and genotype frequencies in populations. The common morning glory plant, Ipomoea purpurea, has a ra
- November 2021, Paper 2, Q19(a)(i) (1 mark): The chromosomes used to determine sex inheritance are given different letters in birds and mammals. Identify one other way in which the sex determination in bir
- November 2021, Paper 2, Q19(a)(ii) (4 marks): A pigeon is a bird. The colour of pigeon feathers is determined by a single gene on the Z chromosome. The feather colour gene has three alleles. ZA = red ZB = b
- November 2021, Paper 2, Q19(b)(i) (2 marks): A student performed a chi squared calculation on the phenotypes of the actual nine children. Part of the calculation is shown in Table 19.1. (O–E)2 Observed Exp
- November 2021, Paper 2, Q19(b)(ii) (1 mark): Table 19.2 shows part of a statistical table for the chi squared test. 99 95 90 10 5.0 1.0 0.5 p% v = 1 .0001 .0039 .0158 2.706 3.841 6.635 7.879 2 .0201 0.103
- November 2021, Paper 2, Q19(b)(iii) (2 marks): The calculated value for χ2 was below the critical value. The student concluded that their expected ratio of 2 : 1 : 1 was incorrect and should be rejected. Eva
- November 2021, Paper 2, Q19(c) (2 marks): Hypophosphatemic rickets is a sex-linked condition. The diagram shows the occurrence of hypophosphatemic rickets in a single family. healthy male healthy female
- November 2021, Paper 2, Q20(a)(i) (1 mark): Identify the modal beak size of G. fuliginosa. Size = arbitrary units [1]
- November 2021, Paper 2, Q20(a)(ii) (2 marks): Calculate the range of G. fuliginosa beak size as a proportion of the range of G. fortis beak size. Give your answer to 2 significant figures. Proportion = [2]
- November 2021, Paper 2, Q20(a)(iii) (3 marks): The scientists concluded that the data showed evidence of disruptive selection in the population of G. fortis. In disruptive selection, extreme phenotypes are s
- November 2021, Paper 2, Q20(b)(i) (1 mark): Name the type of speciation that occurs when two populations live in the same location. [1]
- November 2021, Paper 2, Q20(b)(ii) (1 mark): Suggest how G. fortis with large beaks could become reproductively isolated from G. fortis with small beaks despite living in the same location. [1]
- November 2021, Paper 2, Q20(c) (6 marks): Charles Darwin visited the Galapagos Islands in the 1820s. The organisms living on the Galapagos Islands provided Darwin with evidence that helped him to develo
- November 2021, Paper 3, Q1(c)(ii) (1 mark): Explain how the high occurrence of CPF in West Highland Terriers could have been a result of artificial selection. [1]
- November 2020, Paper 2, Q7 (1 mark): Scientists self-pollinated some pea plants that were heterozygous for the gene controlling height. 7 They expected a 3:1 ratio of tall plants to short plants in
- November 2020, Paper 2, Q18(b)(i) (4 marks): Represent the data in the table as a bar chart on the grid provided below. [4]
- November 2020, Paper 2, Q18(b)(ii) (3 marks): Since 1940, people have believed that the ability to roll the tongue is caused by a single gene with two alleles. R is dominant and allows tongue-rolling. r is
- November 2020, Paper 2, Q18(b)(iii) (2 marks): Individuals within populations vary. Much of this variation is under genetic control. The Hardy-Weinberg principle might not give an accurate estimate of the pr
- November 2020, Paper 2, Q19(a)(ii) (2 marks): Suggest why Hydra reproduces asexually when conditions are favourable. .. [2]
- November 2020, Paper 2, Q19(b)(i) (6 marks): When conditions are not favourable, Hydra reproduces sexually. This often happens in the winter. Cells in the body wall produce sperms and eggs by meiosis. Larg
- November 2020, Paper 2, Q19(b)(ii) (1 mark): [1]
- June 2019, Paper 2, Q6 (1 mark): Meiosis is an important feature of sexual reproduction. Which of the following processes occurs during meiosis and contributes to genetic variation in the offsp
- June 2019, Paper 2, Q8 (1 mark): Which of the following is not associated with the use of artificial selection in farm animals? A health problems in more productive breeds B inbreeding C increa
- June 2019, Paper 2, Q13 (1 mark): The ability to roll one’s tongue is under the control of a single gene. The gene has two alleles R and r. People who can roll their tongues can have the genotyp
- June 2019, Paper 3, Q4(b) (6 marks): (b)* The specific immune response involves B and T lymphocytes. There is variation in specific immune responses between individual animals. Variation between im
- June 2018, Paper 2, Q18 (6 marks): 18* For centuries, artificial selection has been used to improve the quality of crop plants used for human consumption. Explain, with reference to selective bre
- June 2018, Paper 2, Q20(b)(ii) (2 marks): It is thought that the modern cheetah population has low genetic diversity because the population, relatively recently, experienced a genetic bottleneck. Explai
- June 2018, Paper 2, Q20(b)(iii) (2 marks): Scientists are concerned about genetic drift in the remaining cheetah populations. Explain why genetic drift is likely to be of particular concern in the popula
- June 2018, Paper 2, Q20(c)(ii) (4 marks): When the island of Madagascar became separated from the African continent, there were no members of the cat family, Felidae, on the island. Outline how a fossa
- June 2018, Paper 2, Q20(c)(iii) (3 marks): Islands, such as Madagascar, often have species that are different from those on the nearest land mass because they are reproductively isolated. State three oth
- June 2018, Paper 3, Q1(c)(i) (3 marks): Identify the following: The genotype of the white onion plant The genotype of the red onion plant The phenotype of the offspring [3]
- June 2018, Paper 3, Q1(c)(ii) (1 mark): State the type of gene interaction shown by the genes A/a and B/b. [1]
- June 2018, Paper 3, Q4(a)(ii) (4 marks): Fig. 4 shows the inheritance pattern of agammaglobulinemia in a family. Key 1 2 male with agammaglobulinemia female with agammaglobulinemia 3 6 4 5 healthy male
- June 2018, Paper 3, Q4(b)(i) (1 mark): Two carriers of Vici syndrome have six children. Calculate how many of the six children you would expect to: • have Vici syndrome • be carriers of Vici syndrome
- June 2018, Paper 3, Q4(b)(ii) (1 mark): A daughter of these parents and a male carrier of Vici syndrome have a child. Calculate the probability of the child having Vici syndrome. Answer = [1]
- June 2017, Paper 2, Q17(a)(i) (1 mark): List the gametes that would be produced by a sweet pea plant that was heterozygous for both seed colour and shape. [1]
- June 2017, Paper 2, Q17(a)(ii) (2 marks): List the genotypes of the offspring that were produced from Mendel’s cross and state the corresponding phenotypes. genotypes phenotypes [2]
- June 2017, Paper 2, Q17(b)(i) (3 marks): Use the chi-squared formula | = E You may use the table below for working out. |2 = [3] 14 Table 17 shows a |2 probability table. Degrees Probability (p) of 0.9
- June 2017, Paper 2, Q17(b)(ii) (3 marks): After analysing the results, the students stated that the inheritance of the seed colour and shape in their investigation was different from that in Mendel’s in
- June 2017, Paper 2, Q17(b)(iii) (3 marks): A ratio that is different from the expected 9 : 3 : 3 : 1, in a cross such as this, can be the result of epistasis. Suggest and explain one reason, other than e
- June 2017, Paper 2, Q17(c)(ii) (1 mark): With reference to the proteins coded for by the seed colour gene, explain why the y allele is recessive. [1]
- June 2017, Paper 3, Q3(b) (3 marks): One subspecies of tiger is the Bengal tiger. One in 10 000 Bengal tiger births results in a white Bengal tiger. White Bengal tigers (shown in Fig. 3.1b on the i
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