Redox I: Edexcel A‑Level Chemistry questions
Every Edexcel A-Level Chemistry exam question on 3 Redox I, 2016–2025, with its mark scheme and examiner’s report.
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Calculations
Q6(b)
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Q6(c)
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Q3(b)
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Q4(c)(i)
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Q5(f)
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Q9(a)
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Q9(b)(i)
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Q9(b)(ii)
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Q9(b)(iii)
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Q2(c)(iii)
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Q3(a)(i)
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Q3(a)(iv)
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Q4(c)
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Q6(a)(i)
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Q6(a)(ii)
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Q6(b)
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Q2(c)
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Q6(c)(ii)
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Q8(c)(i)
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Q8(d)(i)
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All 45 questions on Redox I, as a list
- June 2025, AS Paper 1, Q6(b) (1 mark): Which change in oxidation number of sulfur, if any, occurs during the formation of H2S? (1) A from +6 to −2 B from +6 to +2 C from +2 to −2 D no change
- June 2025, AS Paper 1, Q6(c) (2 marks): Deduce the two ionic half-equations for this reaction. State symbols are not required. (2) Oxidation half-equation Reduction half-equation
- June 2024, Paper 2, Q3(b) (3 marks): Hydrogen peroxide decomposes to form water and oxygen. 2H2O2(aq) → 2H2O(l) + O2(g) Explain, using oxidation numbers, why the decomposition of hydrogen peroxide
- June 2024, Paper 3, Q4(c)(i) (1 mark): Complete the ionic equation for this redox reaction, using oxidation numbers. State symbols are not required. (1) – + OH– + H2O → Al(OH)4 – + NH3 8Al + NO3
- June 2024, AS Paper 1, Q5(f) (1 mark): What is the oxidation number of oxygen in the chlorate(III) ion, ClO2 – ? (1) A −1 B +1 C −2 D +2
- June 2024, AS Paper 1, Q9(a) (1 mark): Iodine is reduced by thiosulfate ions. The relevant half‑equations are shown. ½I2 + e– → I– 2– → S4O6 2– + 2e– 2S2O3 Deduce an overall equation for this reactio
- June 2024, AS Paper 1, Q9(b)(i) (1 mark): State a reason why this is not a disproportionation reaction. (1)
- June 2024, AS Paper 1, Q9(b)(ii) (1 mark): Identify the reducing agent in this reaction. (1)
- June 2024, AS Paper 1, Q9(b)(iii) (1 mark): Which is the half‑equation for the chlorate(I) ion, ClO– , in this reaction? (1) A ClO– + Cl– → Cl2 + ½O2 + 2e– B ClO– + H+ + e– → ½Cl2 + OH– C ClO– + 2H+ + e–
- June 2023, Paper 3, Q2(c)(iii) (2 marks): Show, by reference to oxidation number changes, that the decomposition of sodium nitrate is a redox reaction. (2)
- June 2023, AS Paper 1, Q3(a)(i) (1 mark): What happens to the atoms of a metal and the Group 7 element when they react together? (1) Metal Group 7 element A gains electrons to form a positive ion loses
- June 2023, AS Paper 1, Q3(a)(iv) (1 mark): Platinum metal reacts with fluorine to give a compound of platinum with an oxidation number of +6. Give the formula of this compound of platinum. (1)
- June 2023, AS Paper 1, Q4(c) (1 mark): Bottles of potassium manganate(VII), KMnO4 , have three hazard warning labels. One of these is shown. This hazard symbol means that potassium manganate(VII) is
- June 2023, AS Paper 1, Q6(a)(i) (1 mark): State, in terms of electron transfer, what you understand by the terms oxidation and reduction. (1)
- June 2023, AS Paper 1, Q6(a)(ii) (2 marks): Explain, in terms of electron transfer, which of the species is the oxidising agent and which is the reducing agent. (2)
- June 2023, AS Paper 1, Q6(b) (4 marks): Bromine reacts with sodium hydroxide solution in a disproportionation reaction –. to form BrO3 Complete the equation for this disproportionation. Justify the ba
- June 2022, Paper 1, Q2(c) (2 marks): Calcium reacts with chlorine. Ca(s) + Cl2(g) → CaCl2(s) Explain, in terms of electrons, why this is a redox reaction. (2)
- June 2022, Paper 2, Q6(c)(ii) (1 mark): The oxidising agent is acidified Na2Cr2O7 . State the oxidation number of chromium in Na2Cr2O7 . (1)
- June 2022, AS Paper 1, Q8(c)(i) (1 mark): Deduce the half‑equation for the formation of chlorine. (1)
- June 2022, AS Paper 1, Q8(d)(i) (2 marks): Explain, using oxidation numbers, why this is a disproportionation reaction. (2)
- November 2021, Paper 3, Q1(b) (1 mark): Write the formula of potassium chlorate(V). (1)
- November 2021, AS Paper 1, Q6(b)(i) (2 marks): At room temperature the reaction that occurs is Cl2 + NaOH → NaClO + NaCl Explain, with reference to oxidation numbers, why this is a disproportionation reactio
- November 2021, AS Paper 1, Q6(c)(i) (2 marks): Calculate the number of moles of electrons gained by chlorine molecules during this reaction. [Under these conditions one mole of gas occupies 24 dm3] (2)
- November 2021, AS Paper 1, Q6(c)(ii) (3 marks): The reducing agent was a solution containing thiosulfate ions, S2O3 The chlorine reacted with 40 cm3 of a 0.20 mol dm–3 solution of these ions. Deduce the numbe
- October 2020, Paper 1, Q8(b)(ii) (1 mark): Determine the oxidation number of carbon in the ethanedioate ion, C2O4 (1)
- October 2020, Paper 2, Q3(a)(i) (2 marks): Explain, in terms of oxidation numbers, whether or not this is a disproportionation reaction. (2)
- June 2019, Paper 3, Q5(a) (1 mark): Name the ion with formula PO3 (1)
- June 2019, Paper 3, Q5(b) (1 mark): State what happens to a reducing agent during a reaction, in terms of oxidation number and electrons. (1)
- June 2019, Paper 3, Q5(d)(ii) (1 mark): Give a reason why this reaction is not disproportionation. (1)
- June 2019, AS Paper 1, Q9(a)(i) (1 mark): This reaction is an example of (1) A oxidation only B reduction only C disproportionation D decomposition
- June 2019, AS Paper 1, Q9(b)(i) (1 mark): The following reaction occurs when potassium chlorate(V) is heated at a suitable temperature. Complete the equation by balancing it. State symbols are not requi
- June 2018, Paper 1, Q10(a) (1 mark): Write the equation for the reaction of copper with concentrated nitric acid, using the half-equations given in Step 1. State symbols are not required. (1)
- June 2018, Paper 2, Q4(b) (3 marks): The second reaction in the airbag is between the sodium produced in the reaction (a)(i) and potassium nitrate. Na + KNO3 → K2O + Na2O + N2 Balance the above equ
- June 2018, Paper 2, Q5(a) (2 marks): Balance the ionic half-equation for the reduction of the dichromate(VI) ion. Give the colours of all of the species involved, or state colourless if appropriate
- June 2018, AS Paper 1, Q6(b)(i) (2 marks): Complete the table by identifying the oxidation numbers of sulfur in the three sulfur-containing ions. (2) Ion Oxidation number of sulfur 2− S2O3 SO4 2− 2− S4O6
- June 2018, AS Paper 1, Q6(b)(ii) (1 mark): The equation for the reaction of iodine with thiosulfate ions is 2− + I2 → 2I− + S4O6 2− 2S2O3 State, in terms of electrons, why iodine is classified as an oxid
- June 2018, AS Paper 1, Q6(b)(iii) (1 mark): Use your answer to b(i) to show that chlorine is a stronger oxidising agent than iodine. (1)
- June 2018, AS Paper 1, Q6(b)(iv) (2 marks): Chlorine reacts in aqueous solution with S2O3 2− to give SO4 2−. The ionic half-equation for the reaction of chlorine is Cl2 + 2e− → 2Cl− 2− to give SO4 2−. Wri
- June 2018, AS Paper 1, Q6(b)(v) (1 mark): Use your answer to (b)(iv) and the half-equation for chlorine, to write the overall ionic equation for the reaction between chlorine and thiosulfate ions. State
- June 2017, Paper 1, Q2(a) (3 marks): Explain, in terms of all the relevant oxidation numbers, why this is a redox reaction. (3)
- June 2017, AS Paper 1, Q4(a)(i) (1 mark): Write an ionic half-equation for the reduction of chlorine molecules to chloride ions. State symbols are not required. (1)
- June 2017, AS Paper 1, Q4(a)(ii) (1 mark): Write an ionic half-equation for the oxidation of chlorine molecules to chlorate(I) ions in the presence of cold, aqueous hydroxide ions. State symbols are not
- June 2017, AS Paper 1, Q4(a)(iii) (1 mark): Combine the two equations in (a)(i) and (ii) to give the ionic equation for the reaction of chlorine molecules with cold, aqueous hydroxide ions. (1)
- June 2017, AS Paper 1, Q4(a)(iv) (2 marks): Use your answer to (a)(iii) to explain why the reaction is described as a disproportionation reaction. (2)
- June 2016, AS Paper 1, Q8(b)(iii) (3 marks): Explain, by using the oxidation numbers of all the atoms, whether or not this is a redox reaction. (3)
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