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Gibbs free-energy change, ∆G, and entropy change, ∆S: AQA A‑Level Chemistry questions

AQA A-Level Chemistry past-paper questions on 3.1.8.2 Gibbs free-energy change, ∆G, and entropy change, ∆S, 2008–2025, with mark schemes and examiner’s reports where available.

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  1. Q04.2

    June 2025 · Paper 1

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  2. Q08.8

    June 2024 · Paper 1

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    The start of question 08

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  3. Q01.7

    June 2022 · Paper 3

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  4. Q01.8

    June 2022 · Paper 3

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  5. Q07.1

    November 2021 · Paper 1

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  6. Q07.2

    November 2021 · Paper 1

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    The start of question 07

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  7. Q07.3

    November 2021 · Paper 1

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  8. Q10.1

    November 2020 · Paper 1

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    The start of question 10

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  9. Q10.2

    November 2020 · Paper 1

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  10. Q10.3

    November 2020 · Paper 1

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  11. Q03.1

    June 2018 · Paper 1

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  12. Q03.2

    June 2018 · Paper 1

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  13. Q03.3

    June 2018 · Paper 1

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  14. Q05.1

    June 2017 · Paper 1

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  15. Q01.4

    June 2017 · Paper 3

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  17. Q05.1

    Specimen · Paper 1

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  18. Q05.2

    Specimen · Paper 1

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  20. Q6(b)

    June 2016 · CHEM5 (old spec)

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All 91 questions on Gibbs free-energy change, ∆G, and entropy change, ∆S, as a list
  1. June 2025, Paper 1, Q04.2 (5 marks): Use the equation and the data in Table 4 to calculate the temperature at which this reaction becomes feasible. [5 marks] Temperature K
  2. June 2024, Paper 1, Q08.8 (3 marks): Calculate the temperature, in °C, at which this reaction becomes feasible. NaCl(s) → Na(s) + 1 2 Cl2(g) ΔH = +411 kJ mol–1 ΔS = +90.1 J K–1 mol–1 [3 marks] Temp
  3. June 2022, Paper 3, Q01.7 (4 marks): Table 3 shows some entropy data at 298 K Table 3 Entropy S / J K 1 mol 1 NH4NO3(s) 151 NH4+(aq) 113 NO3−(aq) 146 Calculate a value for the Gibbs free-energy cha
  4. June 2022, Paper 3, Q01.8 (2 marks): Ammonium nitrate decomposes as shown. NH4NO3(s) → N2 (g) + 1 2 O2 (g) + 2 H2 O (g) ∆H = +123 kJ mol−1 The entropy change (∆S) for this reaction is +144 J K–1 mo
  5. November 2021, Paper 1, Q07.1 (1 mark): Explain why the standard entropy value for carbon dioxide is greater than that for carbon. [1 mark]
  6. November 2021, Paper 1, Q07.2 (1 mark): State the temperature at which the standard entropy of aluminium is 0 J K–1 mol–1 [1 mark]
  7. November 2021, Paper 1, Q07.3 (7 marks): Use the equation and the data in Table 7 to calculate the minimum temperature, in K, at which this reaction becomes feasible. [7 marks] Minimum temperature K
  8. November 2020, Paper 1, Q10.1 (6 marks): Use the equation and the data in Table 5 to calculate the Gibbs free-energy change (ΔG), in kJ mol–1, for this reaction at 890 K [6 marks] ΔG kJ mol–1
  9. November 2020, Paper 1, Q10.2 (4 marks): Use the values of the intercept and gradient from the graph in Figure 4 to calculate the enthalpy change (ΔH), in kJ mol–1, and the entropy change (ΔS), in J K–
  10. November 2020, Paper 1, Q10.3 (1 mark): State what Figure 4 shows about the feasibility of the reaction. [1 mark]
  11. June 2018, Paper 1, Q03.1 (2 marks): Calculate the entropy change for the reaction between ammonia and oxygen. [2 marks] Entropy change J K–1 mol–1
  12. June 2018, Paper 1, Q03.2 (2 marks): Calculate a value for the Gibbs free-energy change (ΔG), in kJ mol–1, for the reaction between ammonia and oxygen at 600 °C (If you were unable to obtain an ans
  13. June 2018, Paper 1, Q03.3 (2 marks): The reaction between ammonia and oxygen was carried out at a higher temperature. Explain how this change affects the value of ΔG for the reaction. [2 marks]
  14. June 2017, Paper 1, Q05.1 (6 marks): Some entropy data are shown in Table 3. Table 3 Substance TiO2(s) C(s) Cl2(g) CO(g) TiCl4(l) So / J K−1 mol−1 50.2 5.70 223 198 253 Use the equation and the dat
  15. June 2017, Paper 3, Q01.4 (5 marks): Anhydrous magnesium chloride can be formed by direct reaction between its elements. Mg(s) + Cl2(g) → MgCl2(s) The free-energy change, ∆G, for this reaction vari
  16. June 2017, Paper 3, Q32 (1 mark): A reaction is exothermic and has a negative entropy change. Which statement is correct? [1 mark] A The reaction is always feasible B The reaction is feasible ab
  17. Specimen, Paper 1, Q05.1 (4 marks): Free-energy change = Units = 3
  18. Specimen, Paper 1, Q05.2 (2 marks): Temperature = K
  19. Specimen, Paper 1, Q08.5 (2 marks): Explain why the reaction in Question 8.3 occurs despite having an enthalpy change that is approximately zero. [2 marks] 0 8 . 5
  20. June 2016, CHEM5 (old spec), Q6(b) (2 marks): Use data from Table 3 to calculate the standard entropy change for this reaction. [2 marks]
  21. June 2016, CHEM5 (old spec), Q6(c) (1 mark): State what the sign of the entropy change in your answer to part (b) indicates about the product of this reaction relative to the reactants. [1 mark]
  22. June 2016, CHEM5 (old spec), Q6(d) (3 marks): Use your answers to parts (a) and (b) to calculate a value for the free–energy change for this reaction at 50 °C. (If you were unable to calculate ΔH in part (a
  23. June 2016, CHEM5 (old spec), Q6(e) (1 mark): Use your answer to part (d) to explain whether the reaction is feasible at 50 °C [1 mark]
  24. June 2015, CHEM5 (old spec), Q3(a)(ii) (2 marks): Use data from Table 4 to calculate the entropy change, ΔS, for the reaction of steam with methane. [2 marks]
  25. June 2015, CHEM5 (old spec), Q3(b) (4 marks): Use your values of ΔH and ΔS from Questions 3 (a) (i) and 3 (a) (ii) to calculate the temperature above which this reaction is feasible. [4 marks]
  26. June 2015, CHEM5 (old spec), Q3(d)(i) (3 marks): Explain, using a calculation, why this reaction should not occur at 1300 K. [3 marks]
  27. June 2015, CHEM5 (old spec), Q3(d)(ii) (2 marks): Explain how the conditions for the reaction could be changed to allow this reaction to take place. [2 marks]
  28. June 2014, CHEM5 (old spec), Q2(d) (4 marks): Silver chloride is insoluble in water at room temperature. Use data from Table 2 to calculate the temperature at which the dissolving of silver chloride in wate
  29. June 2014, CHEM5 (old spec), Q2(e) (3 marks): When silver fluoride dissolves in water at 25 ºC, the free-energy change is –9 kJ mol–1. Use this information and data from Table 2 to calculate a value, with u
  30. June 2013, CHEM5 (old spec), Q2(c)(i) (3 marks): Explain why the free-energy change for the dissolving of potassium chloride in water is negative, even though the enthalpy change is positive.
  31. June 2013, CHEM5 (old spec), Q3(a)(i) (2 marks): Explain, in terms of molecules, why the entropy is zero when the temperature is zero Kelvin.
  32. June 2013, CHEM5 (old spec), Q3(a)(ii) (2 marks): Explain, in terms of molecules, why the first part of the graph in Figure 1 is a line that slopes up from the origin.
  33. June 2013, CHEM5 (old spec), Q3(a)(iii) (1 mark): On Figure 1, mark on the appropriate axis the boiling point (Tb) of substance X. (1 mark)
  34. June 2013, CHEM5 (old spec), Q3(a)(iv) (2 marks): In terms of the behaviour of molecules, explain why L2 is longer than L1 in Figure 1.
  35. June 2013, CHEM5 (old spec), Q3(b)(i) (2 marks): Explain, with the aid of a thermodynamic equation, why this line obeys the mathematical equation for a straight line, y = mx + c.
  36. June 2013, CHEM5 (old spec), Q3(b)(ii) (1 mark): Explain why the magnitude of ΔG decreases as T increases in this reaction. (1 mark)
  37. June 2013, CHEM5 (old spec), Q3(b)(iii) (1 mark): State what you can deduce about the feasibility of this reaction at temperatures lower than 500 K. (1 mark)
  38. June 2013, CHEM5 (old spec), Q3(c)(i) (1 mark): Calculate the entropy change ΔS for this reaction. (1 mark)
  39. June 2013, CHEM5 (old spec), Q3(c)(ii) (3 marks): Calculate a value, with units, for the enthalpy change for this reaction at 5440 K. (If you have been unable to answer part (c) (i), you may assume that the val
  40. January 2013, CHEM5 (old spec), Q3(a) (2 marks): Suggest how these quantities can be used to predict whether a change is feasible.
  41. January 2013, CHEM5 (old spec), Q3(b) (4 marks): Explain why the evaporation of water is spontaneous even though this change is endothermic. In your answer, refer to the change in the arrangement of water mole
  42. January 2013, CHEM5 (old spec), Q3(c)(i) (4 marks): Calculate the temperature above which the reaction between hydrogen and oxygen to form gaseous water is not feasible.
  43. January 2013, CHEM5 (old spec), Q3(c)(ii) (2 marks): State what would happen to a sample of gaseous water that was heated to a temperature higher than that of your answer to part (c) (i). Give a reason for your an
  44. January 2013, CHEM5 (old spec), Q3(d) (3 marks): When hydrogen is used as a fuel, more heat energy can be obtained if the gaseous water formed is condensed into liquid water. Use entropy data from the table in
  45. June 2012, CHEM5 (old spec), Q2(a) (1 mark): Write an equation to show the relationship between ΔG, ΔH and ΔS. (1 mark)
  46. June 2012, CHEM5 (old spec), Q2(b) (3 marks): Use the graph to calculate a value for the slope (gradient) of the line. Give the units of this slope and the symbol for the thermodynamic quantity that this sl
  47. June 2012, CHEM5 (old spec), Q2(c) (2 marks): Explain the significance, for this reaction, of temperatures below the temperature value where the line crosses the temperature axis.
  48. June 2012, CHEM5 (old spec), Q2(d) (1 mark): The line is not drawn below a temperature of 240 K because its slope (gradient) changes at this point. Suggest what happens to the ammonia at 240 K that causes
  49. June 2012, CHEM5 (old spec), Q3(d)(ii) (1 mark): Suggest why the entropy change for dissolving silver fluoride in water has a positive value. (1 mark)
  50. June 2012, CHEM5 (old spec), Q3(d)(iii) (2 marks): Explain why the dissolving of silver fluoride in water is always a spontaneous process.
  51. June 2012, CHEM5 (old spec), Q4(b) (2 marks): Calculate the entropy change for this reaction.
  52. June 2012, CHEM5 (old spec), Q4(c) (2 marks): Calculate the temperature below which this reaction is spontaneous.
  53. June 2012, CHEM5 (old spec), Q4(d) (1 mark): Suggest one reason why nitrogen dioxide is not formed by this reaction in an internal combustion engine. (1 mark)
  54. June 2012, CHEM5 (old spec), Q4(f) (2 marks): Use your equation from part (e) to explain why the free-energy change for the reaction to form nitrogen monoxide stays approximately constant at different tempe
  55. January 2012, CHEM5 (old spec), Q1(e) (1 mark): The standard free-energy change for the formation of magnesium oxide from magnesium and oxygen, ΔGf = –570 kJ mol–1. Suggest one reason why a sample of magnesiu
  56. January 2012, CHEM5 (old spec), Q1(f) (3 marks): Use the value of ΔGf given in part (e) and the value of ΔHf from part (c) to calculate a value for the entropy change ΔS when one mole of magnesium oxide is for
  57. January 2012, CHEM5 (old spec), Q1(g) (2 marks): In terms of the reactants and products and their physical states, account for the sign of the entropy change that you calculated in part (f).
  58. January 2012, CHEM5 (old spec), Q2(c) (3 marks): Calculate the temperature at which ΔG = 0 for this process. Show your working.
  59. June 2011, CHEM5 (old spec), Q2(a) (1 mark): Write an equation, including state symbols, for the process that occurs when potassium nitrate dissolves in water. (1 mark)
  60. June 2011, CHEM5 (old spec), Q2(b) (1 mark): Suggest why the entropy change for this process is positive. (1 mark)
  61. June 2011, CHEM5 (old spec), Q2(c) (3 marks): Calculate the temperature at which the free-energy change, ΔG, for this process is zero.
  62. June 2011, CHEM5 (old spec), Q2(d)(i) (1 mark): Deduce what happens to the value of ΔG when potassium nitrate dissolves in water at a temperature lower than your answer to part 2 (c). (1 mark)
  63. June 2011, CHEM5 (old spec), Q2(d)(ii) (1 mark): What does this new value of ΔG suggest about the dissolving of potassium nitrate at this lower temperature? (1 mark)
  64. June 2011, CHEM5 (old spec), Q3(b) (3 marks): The table below contains some entropy data. Use these data to calculate a value for the entropy change, with units, for the formation of one mole of ammonia fro
  65. June 2011, CHEM5 (old spec), Q3(c)(i) (3 marks): Use the ΔH value of –46 kJ mol–1 and your answer from part 3 (b) to calculate a value for ΔG, with units, for the synthesis at this temperature. (If you have be
  66. June 2011, CHEM5 (old spec), Q3(c)(ii) (1 mark): Use the value of ΔG that you have obtained to comment on the feasibility of the reaction at 800 K. (1 mark)
  67. January 2011, CHEM5 (old spec), Q2(a) (2 marks): Explain why the entropy value for the element nitrogen is much greater than the entropy value for the element carbon (graphite). (2 marks)
  68. January 2011, CHEM5 (old spec), Q2(b) (1 mark): Suggest the condition under which the element carbon (diamond) would have an entropy value of zero. (1 mark)
  69. January 2011, CHEM5 (old spec), Q2(c) (1 mark): Write the equation that shows the relationship between ΔG, ΔH and ΔS for a reaction. (1 mark)
  70. January 2011, CHEM5 (old spec), Q2(d) (1 mark): State the requirement for a reaction to be feasible. (1 mark)
  71. January 2011, CHEM5 (old spec), Q2(e) (5 marks): Consider the following reaction that can lead to the release of the pollutant NO into the atmosphere. N2(g) + O2(g) →NO(g) Use data from the table on page 4 to
  72. January 2011, CHEM5 (old spec), Q2(f) (1 mark): At temperatures below the value calculated in part 2 (e), decomposition of NO into its elements should be spontaneous. However, in car exhausts this decompositi
  73. January 2011, CHEM5 (old spec), Q2(g) (3 marks): A student had an idea to earn money by carrying out the following reaction. C(graphite) →C(diamond) Use data from the table on page 4 to calculate values for ΔH
  74. June 2010, CHEM5 (old spec), Q6(b) (3 marks): Calculate the standard entropy change for this reaction.
  75. June 2010, CHEM5 (old spec), Q6(c) (6 marks): Use your answers to parts (a) and (b) to explain why this reaction is not feasible at high temperatures. Calculate the temperature at which the reaction becomes
  76. June 2010, CHEM5 (old spec), Q6(d) (4 marks): Write an equation for the complete combustion of methanol. Use your equation to explain why the combustion reaction in the gas phase is feasible at all temperat
  77. January 2010, CHEM5 (old spec), Q5(a) (1 mark): State why the entropy value for ammonia is equal to zero at 0K. (1 mark)
  78. January 2010, CHEM5 (old spec), Q5(b) (1 mark): Explain, in terms of the movement of particles, why the entropy value increases between points A and B on the diagram. (1 mark)
  79. January 2010, CHEM5 (old spec), Q5(c) (1 mark): Temperature T is marked on the diagram. What does the value of this temperature represent? (1 mark)
  80. January 2010, CHEM5 (old spec), Q5(d) (2 marks): Explain why there is a large entropy change between points D and E on the diagram. (2 marks)
  81. January 2010, CHEM5 (old spec), Q5(e)(i) (2 marks): Calculate a value for the entropy change, ∆S , for the formation of one mole of ammonia.
  82. January 2010, CHEM5 (old spec), Q5(e)(ii) (4 marks): Give the equation that relates free-energy change, ∆G , to enthalpy change, ∆H , and entropy change, ∆S . Use this equation to calculate the temperature at whic
  83. January 2010, CHEM5 (old spec), Q5(e)(iii) (1 mark): What can you deduce about the formation of ammonia if the reaction mixture is heated to a temperature above the value that you have calculated in part (e) (ii)?
  84. June 2008, CHM5 (2008 spec), Q2(a) (1 mark): 2 (a) State the equation that relates free-energy change, ∆G, to enthalpy change, ∆H, and entropy change, ∆S. (1 mark)
  85. June 2008, CHM5 (2008 spec), Q2(b) (1 mark): 2 (b) Suggest why the free-energy change is equal to zero (∆G = 0) when a liquid boils. (1 mark)
  86. June 2008, CHM5 (2008 spec), Q2(c) (2 marks): 2 (c) Use data from the table above to calculate the standard entropy change, in J K–1 mol–1, when liquid ammonia boils. (2 marks)
  87. June 2008, CHM5 (2008 spec), Q3(b) (3 marks): 3 (b) Using data from the table above calculate the entropy change for the formation of one mole of ammonia from its elements. (3 marks)
  88. June 2008, CHM5 (2008 spec), Q3(c) (3 marks): 3 (c) (i) Use your answer from part (b) and data from the table to calculate the value of the free-energy change, ∆G, for the formation of one mole of ammonia f
  89. June 2008, CHM5 (2008 spec), Q3(d) (1 mark): 3 (d) Suggest one advantage, in industry, of operating this reaction at temperatures higher than 700 K. (1 mark)
  90. June 2008, CHM6W (2008 spec), Q29 (1 mark): 29 Chlorine trifluoride can be decomposed into its elements: 2ClF3(g) Cl2(g) 3F2(g) ∆H = +159 kJ mol–1 colourless green yellow gas gas gas Correct statements in
  91. June 2008, CHM6W (2008 spec), Q40 (1 mark): 40 Consider the following reaction, which involves the breaking of only one covalent bond. O2N–NO2(g) →2NO2(g) Correct statements include 1 ∆H is positive. 2 ∆G

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