Sec, cosec, cot and inverse trig functions: OCR MEI A‑Level Maths questions
OCR MEI A-Level Maths past-paper questions on 5.5 Sec, cosec, cot and inverse trig functions, 2018–2025, with mark schemes and examiner’s reports where available. Add MadAsMaths questions to your practice, or browse them separately by topic and difficulty.
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All 10 questions on Sec, cosec, cot and inverse trig functions, as a list
- June 2025, Paper 2, Q6 (2 marks): The diagram shows part of the graph of f( ) x cosec 2 x . = y 1 x 0 – 1 1 (a) State which of the following is the equation of the curve y . = f( ) x y cos 2 x y
- June 2024, Paper 3, Q6 (5 marks): In this question you must show detailed reasoning. Solve the equation tan x 3 cot x 2 for values of x in the interval 0 ° G x 360 ° . [5] - = G
- June 2022, Paper 1, Q3 (8 marks): (a) Sketch the graph of y arctan x where x is in radians. [2] = (b) In this question you must show detailed reasoning. 2 Find all points of intersection of the
- November 2021, Paper 1, Q6 (7 marks): (a) The diagram shows part of the graph of y cosec x , where x is in radians. = State the equations of the three vertical asymptotes that can be seen. [1] y x O
- November 2021, Paper 3, Q12 (3 marks): c m, as given in line 15. 1 12 Show that arctan 3 [3] b =
- November 2021, Paper 3, Q13 (3 marks): c m 1 r 13 (a) Use triangle ABE in Fig. C2 to show that arctan x arctan , as given in line 29. [1] + = 2 x (b) Sketch the graph of y arctan x . [1] = c m, as gi
- November 2021, Paper 3, Q14 (5 marks): (a) Show that c m c m c m c m 1 c 1 m 1 1 1 & arctan arctan arctan arctan arctan arctan 1 . [1] + = + = 2 n 1 n n n 2 3 1 + + + (b) Use the arctan addition form
- November 2021, Paper 3, Q15 (4 marks): Prove that arctan 1 arctan 2 arctan 3 , as given in line 41. [4] + + = r
- November 2020, Paper 3, Q5 (11 marks): Fig. 5 shows part of the curve y = cosec x together with the x- and y-axes. y x O Fig. 5 (a) For the section of the curve which is shown in Fig. 5, write down (
- June 2019, Paper 1, Q10 (7 marks): 10 (a) Express cos 7 x 2 sin x in the form R cos ( x ) where R 2 0 and 0 1 1 r, giving the - + a a 2 exact value of R and the value of a correct to 3 significan
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