Kinetics: OCR A‑Level Chemistry B questions
Every OCR A-Level Chemistry B exam question on CI Kinetics (specification points CI(a)–(e)), 2016–2025, with its mark scheme and examiner’s report.
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Q35(a)(iii)
The whole paper ↗
Q3(a)
The whole paper ↗![June 2025 Paper 2, question 3(a): Explain why a large excess of Cl 2 is required. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-a-qp.webp?v=3)
Q3(b)
The whole paper ↗![June 2025 Paper 2, question 3(b): Use the graph to work out the initial rate of the reaction in mol dm–3 s–1. Show your working on the graph. Initial rate = mol dm–3 s–1 [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-b-qp.webp?v=3)
Q3(c)(i)
The whole paper ↗![June 2025 Paper 2, question 3(c)(i): What can the scientists conclude from this? [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-ci-qp.webp?v=3)
Q3(c)(ii)
The whole paper ↗![June 2025 Paper 2, question 3(c)(ii): Fill in the missing value in Table 3.1. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-cii-qp.webp?v=3)
Q3(c)(iii)
The whole paper ↗![June 2025 Paper 2, question 3(c)(iii): Plot a graph of initial rate against [NO]2. Use the data in Table 3.1. Include the origin. Draw the line of best fit. [4]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-ciii-qp.webp?v=3)
Q3(c)(iv)
The whole paper ↗![June 2025 Paper 2, question 3(c)(iv): Explain why the graph shows that the reaction is second order with respect to NO. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-civ-qp.webp?v=3)
Q3(d)(i)
The whole paper ↗![June 2025 Paper 2, question 3(d)(i): Complete the rate equation for the reaction. Rate = k × [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-di-qp.webp?v=3)
Q3(d)(ii)
The whole paper ↗![June 2025 Paper 2, question 3(d)(ii): Give the units of the rate constant, k. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-dii-qp.webp?v=3)
Q3(d)(iii)
The whole paper ↗![June 2025 Paper 2, question 3(d)(iii): Explain why the value of the rate constant cannot be calculated from data in this question. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43302-jun25-03-diii-qp.webp?v=3)
Q3(d)(iv)
The whole paper ↗
Q32(a)(i)
The whole paper ↗![June 2024 Paper 1, question 32(a)(i): Use the results to show that the rate equation is: Rate = k[NO]2 [3]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43301-jun24-32-ai-qp.webp?v=3)
Q32(a)(ii)
The whole paper ↗![June 2024 Paper 1, question 32(a)(ii): Calculate the rate constant, k, for the reaction in Equation 32.1 and give its units. k = units [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43301-jun24-32-aii-qp.webp?v=3)
Q32(b)(i)
The whole paper ↗![June 2024 Paper 1, question 32(b)(i): The rate equation for this reaction is: Rate = k[NO2]2 A student says that this reaction takes place in a single step. Explain why this cannot be correct and gi](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43301-jun24-32-bi-qp.webp?v=3)
Q32(b)(ii)
The whole paper ↗

Q4(a)(i)
The whole paper ↗![June 2023 Paper 3, question 4(a)(i): Explain why the results of Experiment 1 show that the rate of reaction does not vary with the iodine concentration. [2]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43303-jun23-04-ai-qp.webp?v=3)
Q4(a)(ii)
The whole paper ↗![June 2023 Paper 3, question 4(a)(ii): During Experiment 1, the students ensured the concentration of propanone remained virtually constant. How did they do this? [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43303-jun23-04-aii-qp.webp?v=3)
Q4(b)
The whole paper ↗![June 2023 Paper 3, question 4(b): Suggest why the total volume is kept constant in Experiment 2. [1]](https://pub-e8a9dbab8e2a4d089f52b2a45e0d0b50.r2.dev/bank/h43303-jun23-04-b-qp.webp?v=3)
All 61 questions on Kinetics, as a list
- June 2025, Paper 1, Q23 (1 mark): A scientist studies the reaction: J K 1 After 24 minutes there is 8 th as much J left as at the start. What is the half-life of the reaction in minutes? A 4 B 6
- June 2025, Paper 1, Q35(a)(iii) (3 marks): A chemist measures the rate constant for this reaction at two temperatures. The chemist’s results are shown in the table. T / K ln k Temperature 1 313 4.777 Tem
- June 2025, Paper 2, Q3(a) (1 mark): Explain why a large excess of Cl 2 is required. [1]
- June 2025, Paper 2, Q3(b) (2 marks): Use the graph to work out the initial rate of the reaction in mol dm–3 s–1. Show your working on the graph. Initial rate = mol dm–3 s–1 [2]
- June 2025, Paper 2, Q3(c)(i) (1 mark): What can the scientists conclude from this? [1]
- June 2025, Paper 2, Q3(c)(ii) (1 mark): Fill in the missing value in Table 3.1. [1]
- June 2025, Paper 2, Q3(c)(iii) (4 marks): Plot a graph of initial rate against [NO]2. Use the data in Table 3.1. Include the origin. Draw the line of best fit. [4]
- June 2025, Paper 2, Q3(c)(iv) (1 mark): Explain why the graph shows that the reaction is second order with respect to NO. [1]
- June 2025, Paper 2, Q3(d)(i) (1 mark): Complete the rate equation for the reaction. Rate = k × [1]
- June 2025, Paper 2, Q3(d)(ii) (1 mark): Give the units of the rate constant, k. [1]
- June 2025, Paper 2, Q3(d)(iii) (1 mark): Explain why the value of the rate constant cannot be calculated from data in this question. [1]
- June 2025, Paper 2, Q3(d)(iv) (3 marks): The scientists conclude that a possible mechanism is as shown below, with step 2 being rate-determining. NO + Cl 2 NOCl 2 Step 1 NOCl 2 + NO 2NOCl Step 2 Give t
- June 2024, Paper 1, Q32(a)(i) (3 marks): Use the results to show that the rate equation is: Rate = k[NO]2 [3]
- June 2024, Paper 1, Q32(a)(ii) (2 marks): Calculate the rate constant, k, for the reaction in Equation 32.1 and give its units. k = units [2]
- June 2024, Paper 1, Q32(b)(i) (3 marks): The rate equation for this reaction is: Rate = k[NO2]2 A student says that this reaction takes place in a single step. Explain why this cannot be correct and gi
- June 2024, Paper 1, Q32(b)(ii) (4 marks): A chemist studies the reaction in Equation 32.2 and measures the rate constant, k, at different temperatures. The chemist plots ln k against 1/T on a graph as s
- June 2023, Paper 1, Q22 (1 mark): A student plots a graph of ln k (y-axis) against 1/T for a reaction. The student draws the straight line of best fit. The Arrhenius equation is ln k = –Ea/RT +
- June 2023, Paper 3, Q4(a)(i) (2 marks): Explain why the results of Experiment 1 show that the rate of reaction does not vary with the iodine concentration. [2]
- June 2023, Paper 3, Q4(a)(ii) (1 mark): During Experiment 1, the students ensured the concentration of propanone remained virtually constant. How did they do this? [1]
- June 2023, Paper 3, Q4(b) (1 mark): Suggest why the total volume is kept constant in Experiment 2. [1]
- June 2023, Paper 3, Q4(c)(i) (1 mark): An extended version of Table 4.1 from the Insert is given below. Use the data in this table to calculate the rates of reaction (in cm3 of iodine solution decolo
- June 2023, Paper 3, Q4(c)(ii) (3 marks): The students do a text book search and find that the rate equation for the reaction is: Rate = k [propanone][H+] Explain whether the results of Experiment 1 and
- June 2023, Paper 3, Q4(d)(i) (1 mark): Show why the rate of reaction of iodine in Run A is 1.1 × 10–5 mol dm–3 s–1. [1]
- June 2023, Paper 3, Q4(d)(ii) (4 marks): Using the data in Table 4.1 for Experiment 2 Run A, calculate the initial concentrations of hydrochloric acid and propanone in the flask. Use these values, alon
- June 2023, Paper 3, Q4(e) (4 marks): A student proposes the reaction mechanism below for the iodination of propanone. O OH Step 1 H+ + + C C H3C CH3 H3C CH3 OH OH Step 2 + H+ + C C H3C CH3 H2C CH3
- June 2023, Paper 3, Q4(f) (1 mark): The students wear safety goggles and protective gloves when carrying out the experiments. Using the information from the insert, suggest one other necessary hea
- June 2022, Paper 2, Q3(a)(i) (3 marks): Use the graph to measure two half-lives to show that the kinetics are first order. Show your working on the graph. first half-life = second half-life = [3]
- June 2022, Paper 2, Q3(a)(ii) (1 mark): Use the graph to measure the initial rate of the reaction in mol dm–3 s–1. initial rate = mol dm–3 s–1 [1]
- June 2022, Paper 2, Q3(a)(iii) (2 marks): The graph shows that the reaction in equation 3.1 is first order with respect to hydrogen peroxide. Explain why the orders with respect to the other reagents ca
- June 2022, Paper 2, Q3(b)(i) (2 marks): Suggest why the tubes go dark blue after a period of time rather than gradually from the start. [2]
- June 2022, Paper 2, Q3(b)(ii) (1 mark): How can the relative rates of reaction be found from the students’ results? [1] 10 2H+ + H2O2 + 2I– I2 + 2H2O Equation 3.1
- June 2022, Paper 2, Q3(c) (6 marks): Some students read about the reaction between hydrogen peroxide and iodide ions as shown in equation 3.1. 2H+ + H2O2 + 2I– I2 + 2H2O Equation 3.1 (c)* The stude
- June 2022, Paper 2, Q3(d) (4 marks): The students find data for the variation of the rate constant, k, with temperature. From their data they plot the graph below. 1 / T / K–1 0 0.0028 0.0029 0.003
- November 2021, Paper 1, Q21 (1 mark): The decomposition of hydrogen peroxide is first order with respect to hydrogen peroxide. The half-life for the decomposition is 900 seconds. What percentage of
- November 2021, Paper 1, Q23 (1 mark): A student determines the rate constant for a reaction at various temperatures and plots ln k against 1 / T. A straight line is produced. The Arrhenius equation
- November 2021, Paper 1, Q35(a)(i) (1 mark): The scientists conclude that the reaction is not first order with respect to N2O. Suggest why they conclude this. [1]
- November 2021, Paper 1, Q35(a)(ii) (3 marks): Plot a graph of rate against the square of concentration on the grid on page 29. [3]
- November 2021, Paper 1, Q35(a)(iii) (1 mark): Use your graph to complete the rate equation for the reaction. Rate = k × [1]
- November 2021, Paper 1, Q35(a)(iv) (3 marks): Use your graph to find a value for the rate constant, k, and give its units. rate constant = units [3]
- November 2021, Paper 1, Q35(b)(i) (2 marks): Use the shape of the graph to give the order of the catalysed reaction with respect to N2O. Explain how you arrived at your answer. [2]
- November 2020, Paper 1, Q21 (1 mark): A student plots ln k (y-axis) against 1 / T (in K−1) for a reaction. The student gets a straight line graph that corresponds to the Arrhenius equation: ln k = −
- November 2020, Paper 3, Q4(a) (6 marks): This question refers to the Practical Insert that is found inside this document. (a)* Method 1 uses a series of titrations to determine the concentration of hyd
- November 2020, Paper 3, Q4(b)(i) (2 marks): Using the data from Table 4.1 in the Practical Insert, plot a graph on the grid below. Include a curve of best fit. 60 50 40 [OH–] ×10–3 / mol dm–3 30 20 10 0 0
- November 2020, Paper 3, Q4(b)(ii) (2 marks): Use your graph to calculate the time taken for the concentration of hydroxide ions to fall from 40 × 10−3 to 20 × 10−3 and from 20 × 10−3 to 10 × 10−3 mol dm−3.
- November 2020, Paper 3, Q4(b)(iii) (2 marks): Explain how the graph shows that the overall order of the reaction is first order. [2]
- November 2020, Paper 3, Q4(b)(iv) (2 marks): A student is told that the reaction followed using Method 1 goes by mechanism B. The student says that the first reaction in mechanism B must be the rate-determ
- November 2020, Paper 3, Q4(c)(i) (2 marks): Use the data in Table 4.2 to determine the order of reaction with respect to 1-bromobutane and hydroxide ions in Method 2. Give your reasoning. [2]
- November 2020, Paper 3, Q4(c)(ii) (1 mark): Complete the rate equation for the reaction in part (c)(i). Rate = [1]
- June 2019, Paper 2, Q4(b)(i) (4 marks): Use the data in the table to plot a graph to determine the half-life for the reaction. Label the axes. half-life = s [4]
- June 2019, Paper 2, Q4(b)(ii) (1 mark): How does the graph show that the reaction in equation 4.1 is first order with respect to N2O5? Draw construction lines on the graph to explain your answer. [1]
- June 2019, Paper 2, Q4(c) (2 marks): The gradient of the graph at 1000 s is 9.8 × 10−5 mol dm−3 s−1. Work out the rate constant for the reaction in equation 4.1 at 315 K. Give the units in your ans
- June 2019, Paper 2, Q4(d) (3 marks): The reaction in equation 4.1 was repeated with a fixed concentration of N2O5 at different temperatures. A graph of l n k against 1 T for the reaction in equatio
- June 2019, Paper 2, Q4(e) (3 marks): A student suggests the following mechanism for the reaction in equation 4.1. The reaction is first order with respect to N2O5. N2O5 → NO2 + NO3 step 1 NO3 → O2
- June 2018, Paper 1, Q16 (1 mark): Which statement about the rate determining step of a reaction is correct? A It is the fast step. B It cannot involve a catalyst. C It does not involve zero orde
- June 2018, Paper 1, Q24 (1 mark): Which statement about the Arrhenius equation is correct? A A plot of ln k against T gives a straight line. B When T is very large ln k almost equals ln A. C Ea
- June 2018, Paper 2, Q3(e)(i) (2 marks): Write the rate equation that would follow from the student’s statement. Give the units of the rate constant. Rate equation: Units of rate constant [2]
- June 2017, Paper 1, Q19 (1 mark): Nitrogen dioxide reacts with carbon monoxide as in the equation below. NO2 + CO NO + CO2 The mechanism is: NO2 + NO2 NO + NO3 Slow NO3 + CO NO2 + CO2 Fast Which
- June 2017, Paper 3, Q2(a)(i) (1 mark): Why was the length of the magnesium ribbon kept the same? [1]
- June 2017, Paper 3, Q2(b) (1 mark): The students predict that the reaction will be second order with respect to acid. Write the rate equation that would be appropriate for this prediction. [1]
- June 2017, Paper 3, Q2(c) (5 marks): The students plot a graph of volume of hydrogen against time. The graph of the results when the concentration of hydrochloric acid is 0.5 mol dm3 is shown below
- June 2017, Paper 3, Q2(d) (6 marks): The students decide to measure the activation enthalpy for the reaction. They repeat the experiment at different temperatures using a fixed concentration of aci
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