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Second order recurrence relations: Edexcel A‑Level Further Maths questions

Edexcel A-Level Further Maths past-paper questions on 9.2 Second order recurrence relations, 2018–2025, with mark schemes and examiner’s reports where available. Add MadAsMaths questions to your practice, or browse them separately by topic and difficulty.

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789 questions

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  2. Q2

    June 2024 · Further Pure 2

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  3. Q8

    June 2024 · Decision 2

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  4. Q6

    June 2023 · Further Pure 2

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  5. Q5

    June 2023 · Decision 2

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  6. Q6

    June 2022 · Further Pure 2

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  7. Q2

    June 2022 · Decision 2

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  8. Q2

    November 2020 · Further Pure 2

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  9. Q4

    November 2020 · Decision 2

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  10. Q3

    June 2019 · Further Pure 2

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  11. Q5

    June 2019 · Decision 2

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All 11 questions on Second order recurrence relations, as a list
  1. June 2025, Further Pure 2, Q4 (9 marks): A sequence is defined by un+2 = 6un+1 – 8un n  1 u1 = 399.6 u2 = 798.4 (a) Prove by induction that, for n ∈  un = 200(2 n) – 1 10 (4 n) (6) (b) Hence determin
  2. June 2024, Further Pure 2, Q2 (5 marks): Determine a closed form for the recurrence system u n u u u u n n n 1 2 2 1 4 6 6 9 1 2 3 ( , , , ) (5)
  3. June 2024, Decision 2, Q8 (8 marks): A sequence {un}, where n  0, satisfies the recurrence relation 2 5 3 8 2 2 1 u u u n n n n (a) Find the general solution of this recurrence relation. (5) A par
  4. June 2023, Further Pure 2, Q6 (7 marks): Determine a closed form for the recurrence relation u u u u u n n n n n 0 1 2 1 1 0 4 2 4 3  (7)
  5. June 2023, Decision 2, Q5 (8 marks): A sequence un ,where n 0, satisfies the second order recurrence relation u u u n n n 2 1 1 2 3 where u u 0 1 15 20 = = (a) By considering the sequence vn , whe
  6. June 2022, Further Pure 2, Q6 (6 marks): (a) Determine the general solution of the recurrence relation u n = 2u n – 1 – u n – 2 + 2n n  2 (4) (b) Hence solve this recurrence relation given that u0 = 2
  7. June 2022, Decision 2, Q2 (4 marks): The general solution of the second order recurrence relation un + 2 + k1un + 1 + k2un = 0 n  0 is given by un = (A + Bn)(–3)n where A and B are arbitrary non‑z
  8. November 2020, Further Pure 2, Q2 (9 marks): Solve the recurrence system u1 = 1 u2 = 4 9un + 2 – 12un + 1 + 4un = 3n (9)
  9. November 2020, Decision 2, Q4 (8 marks): The complementary function for the second order recurrence relation un + 2 + αun + 1 + βun = 20 (−3) n n  0 is given by un = A (2) n + B (−1) n where A and B a
  10. June 2019, Further Pure 2, Q3 (8 marks): The number of visits to a website, in any particular month, is modelled as the number of visits received in the previous month plus k times the number of visits
  11. June 2019, Decision 2, Q5 (11 marks): An increasing sequence {un} for n ` is such that the difference between the nth term of {un} and the mean of the previous two terms of {un} is always 6 (a) Sh

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