Sine and cosine rules: AQA Level 2 Further Maths questions
Every AQA Level 2 Further Maths exam question on 6.3 Sine and cosine rules, 2021–2025, with its mark scheme and examiner’s report.
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All 13 questions on Sine and cosine rules, as a list
- June 2025, Paper 1, Q16 (3 marks): Work out the length AC. Give your answer in the form 2 a where a is an integer. Answer cm
- June 2025, Paper 2, Q14 (5 marks): All lengths shown are in centimetres. 14 (a) Use Pythagoras’ theorem to show that 4w2 – 8w – 21 = 0 14 (b) Work out the size of angle x. x = °
- June 2024, Paper 1, Q12 (3 marks): In triangle ABC, cos A = 3 4 Work out the length BC. Answer cm
- June 2024, Paper 2, Q11 (4 marks): ABC and ACD are triangles. Work out the area of triangle ACD. Answer cm2
- June 2023, Paper 1, Q20 (6 marks): P, Q and R are points on a circle, centre O. Angle POR = 120° PQ = 4 cm QR = 5 cm Work out the radius of the circle. Give your answer in the form √k where k is
- June 2022, Paper 1, Q18 (3 marks): In triangle RST RS : ST = 1 : 4 Work out the exact value of sin θ. Answer
- June 2022, Paper 2, Q16 (4 marks): Here is an isosceles triangle. All the angles are acute. The area of the triangle is 120 cm2 Work out the size of angle y. Answer degrees
- November 2021, Paper 1, Q18 (4 marks): Here is a triangle. Use the cosine rule to work out the value of x. Answer
- November 2021, Paper 2, Q5 (3 marks): SQR is a right-angled triangle. P is a point on SQ. Angle SPR = 45° M is the midpoint of QR. k is a constant. Work out the coordinates of M. Answer ( , )
- Specimen, Paper 1, Q7 (3 marks): ABCD is a rhombus with side length 8 cm Angle ABC = 60o Work out the area of the rhombus. Give your answer in the form a b cm2 where a and b are integers. A C B
- Specimen, Paper 1, Q12 (3 marks): AB = 4 cm AC = 7 cm cos x = – 2 7 A B C x 4 cm 7 cm Work out the length of BC. Answer cm
- Specimen, Paper 2, Q14 (3 marks): Use the sine rule to work out the size of obtuse angle x. Not drawn accurately x 2y y 18° Answer degrees
- Specimen, Paper 2, Q20 (5 marks): VABCD is a pyramid with a horizontal rectangular base ABCD. V is directly above the centre of the base. VA = VB = VC = VD = 10 cm AB = 8 cm BC = 6 cm M is the m
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